What is the most inexpensive chemical available for fluoridation?

What is the most inexpensive chemical available for fluoridation?

• A. Calcium fluoride
• B. Potassium fluoride
• C. Sodium fluoride
• D. Sodium fluorosilicate

Answer: (D)

Sodium fluorosilicate is often considered the most inexpensive chemical available for fluoridation in water treatment processes. This compound is favored due to its cost-effectiveness and is commonly used in municipal water systems to help reduce the incidence of dental cavities among the population. Sodium fluorosilicate dissociates in water, releasing fluoride ions, which are the active component responsible for the dental health benefits. The low cost of sodium fluorosilicate makes it an attractive option for water treatment facilities, especially when scaled for large populations. Other fluoride compounds, while effective, can be more expensive or less favorable due to factors such as availability, ease of handling, and stability. Therefore, sodium fluorosilicate's combination of efficiency and economic viability makes it the preferred choice in many situations where fluoridation is needed.

Sodium fluorosilicate is often considered the most inexpensive chemical available for fluoridation in water treatment processes. This compound is favored due to its cost-effectiveness and is commonly used in municipal water systems to help reduce the incidence of dental cavities among the population.

Sodium fluorosilicate dissociates in water, releasing fluoride ions, which are the active component responsible for the dental health benefits. The low cost of sodium fluorosilicate makes it an attractive option for water treatment facilities, especially when scaled for large populations.

Other fluoride compounds, while effective, can be more expensive or less favorable due to factors such as availability, ease of handling, and stability. Therefore, sodium fluorosilicate's combination of efficiency and economic viability makes it the preferred choice in many situations where fluoridation is needed.